5/8/2011 friday
start = 1.00pm finsh = 4.30pm
compound ( series - parallel ) circuits
To days task was how to created a circuit that has a light bulb in series after two light bulbs in parallel. Then we measured the available voltage at different parts of the series and parallel the measured the volts for
Switch = 12.54v
before parallel light bulb 1 = 12.52v
before parallel light bulb 2 = 12.52v
after parallel light bulb 1 = 8.55v
after parallel light bulb 2 = 8.55v
before series light bulb = 8.55v
after series light bulb 0.00v
Then measured the voltage drop at different parts of the series and parallel to get the voltage drop which is
Across the parallel light bulb 1 = 3.94v
Across the parallel light bulb 2 = 3.94v
Across the series light bulb = 8.42v
Amps
After that we measured the current flowing throught the circuit which is
The switch = 0.60amps
parallel light bulb 1 = 0.17amps
parallel light bulb 2 = 0.43amps
series light bulb = 0.60amps
Watts
calculated watts used at each light bulb which is W=V*I
bulb 1 = 3.83v* 0.17amps = 0.65w
bulb 2 = 3.83v* 0.43amps = 1.64w
series bulb = 8.55v* 0.60amps = 5.13 w
the parallel has the same resistance and the same watts going in where the series has less watts and more resistance so Amps are different as amps depend on the resistance.Voltage is divided between the series bulb and the two parallel bulbs.
good posting-- but what were your results i.e total resistance of the circuit-- how did you calculate it-- total amps and what happens in the compound circuit
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