parallel circuit

 TTEC 4841 - Electrical and Electronics- Practical

Parallel circuit

5/8/2011 friday

start = 1.00pm finsh = 4.30pm



Available voltage

today i learned how to create a parallel circuit with two light bulb. by measuring the available voltage at each light bulb. light bulb1 available voltage 12.49v light bulb2 12.28v


Voltage drop at each light bulb

I used a multimeter to measure the Voltage Drop across each bulb with available voltage of 12.36 v for bulb 1 and 12.30 for bulb 2. the voltage remains the same but in the series circuit the voltage changes because its sharring the bulbs.

Amps

Using a multimeter I measured the current flow ( amps ) through the parrel circuit

current flow through light bulb 1 = 0.73 amps

current flow through light bulb 2 = 0.73 amps

total current flow through both circuits = 1.46amps

 so the amps, watts and the voltage has increased as there is voltage going into  three of them. but the series circuit is the voltage and the amps getting used



Resistance

calculate the total resistance of each light bulb in the circuit which is R=V/I

bulb1 = 12.49v/ 0.73amps = 16.82 ohms

bulb2 = 12.28v/0.73amps = 17.10 ohms

Total resistance

Calculate the total resistance of the circuit.

1/Rt= 1/R1+1/R2

R= 1/16.82  = 0.059omhs

R= 1/17.10 = 0.058ohms

Rt= 0.117ohms

=1/Rt = 1/0.117 = 8.6 ohms


Watts

calculate total watts used in the parallel circuit while both light are on which is W=V/A

W=12.6v*1.46amps = 18.4 ohms

Then calculated each individual bulb which is W=V*A

 bulb 1 = 12.36v* 0.73amps = 9.02 w

bulb 2 = 12.36v* 0.73amps = 9.02 w

the wattage is the same in the parallel circuit so the bulb in the parallel circuit that depend on the resistance going through.












Parallel circuit with 3 light bulbs

we had to measure the current ( amps ) flow through each of the 3 bulb lights bulb circuits. The

current flow through light bulb 1 = 0.32amps

current flow through light bulb 2 = 0.72amps

current flow through light bulb 3 = 0.73amps

and the total current flow through all the circuits. = 1.77amps

so the total amps rises up but the amps in the branch stays the same.

Available volts

Light bulb 1 = 12.44v

Light bulb 2 = 12.44v

Light bulb 3 = 12.44v

voltage drop

light bulb 1 = 12.27v

light bulb 2 = 12.24v

light bulb 3 = 12.22v

I used a multimeter to measure the voltage drop across each light bulb with the available voltage of 12.44v for all the bulbs the available voltage stays the same its not sharing between three light bulb unlike series the voltage is shared between the bulbs.

Resistance

calculate the resistance of each bulb which is R=V/I

bulb 1 = 12.44v/ 0.32amps = 38.875hms

bulb 2 = 12.44v/ 0.72amps = 17.28ohms

bulb 3 = 12.44v / 0.73amps = 17.0ohms

calculate the total resistance of the circuit

1/Rt= 1/R1+1/R2+1/R3

1/38.875= 0.025ohms

1/17.28= 0.081ohms

1/17.04= 0.058ohms

RT= 6.10ohms


Watts

Then calculated the total watts used in the parallel circuit with three light working (on) which is W=V*I

W=12.6*1.77= 21.24 w