individual circuits

TTEC 4841 - Electrical and Electronics- Practical

Individual circuit

03/08/2011 wednesday 

start = 1.00pm finsh = 4.30pm

Today i learned how to use the 12v p/pack supplier to measure the voltage drop across the circuit parts to create a circuit with a small light bulb. i measured the available voltage in the circuit at these points. i measured the amps (current) flowing through the circuit which is wire before ligh bulb. Then calculated the resistance of the light bulb which is R=V/I to get the total Ohms law. Also calculated the watts used at the light bulb which is V*I to get the total watts.

The next step was to measure the available voltage in the circuit by using a voltmeter.

The positive 12v supply (b+)= 14.67v

Terminal before the switch= 14.65v

Terminal after the switch= 14.56v

Terminal before the light bulb= 14.56

Terminal after the light bulb= .01v

The negative on the 12v supply (N-)= .0

After that i measured the voltage drop across the circuit using a voltmeter.

From the B+ of the 12v supply to the input of the switch = 0.02v

from the input of the switch to the output of the switch = 0.02v

from the output of the switch to the input of the bulb = 0.01v

from the input of the bulb to the output of the bulb = 14.87v

from the output of the bulb to the N- of the 12v supply = 14.93 v

 so  the light bulb uses the highest amount of voltage because the bulb has the highest resistance.

Amps:

Then measured the amps ( current  ) flowing through the series circuit with a multimeter so that showed us the amps stays the same throughout the circuit with a total of (amps = 0.42 ohms
Then moved on to calculate the resistance of the bulb. which is R=V/I

= 14.67/0.42
R= 34.92 ohms

so the small bulb has more resistance and less amps flowing through it.

Watts

After that we moved on to calculate watts used at the light bulb which is W=V*A

W= 14.67v*0.42Amps
W=6.1614 w